Let $X$ denote the number of hours you study on a Sunday. It is known that $P(X=x) = \begin{cases} 0.1 & \text{if } x=0 \\ kx & \text{if } x=1, 2 \\ k(5-x) & \text{if } x=3, 4 \\ 0 & \text{otherwise} \end{cases}$ where $k$ is a constant. Then the probability that you study at least two hours on a Sunday is

  • A
    $0.55$
  • B
    $0.15$
  • C
    $0.75$
  • D
    $0.3$

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If a random variable $X$ has the p.d.f. $f(x) = \begin{cases} \frac{k}{x^2+1} & , \text{if } 0 < x < \infty \\ 0 & , \text{otherwise} \end{cases}$,then the c.d.f. of $X$ is:

The following table shows the probability distribution of smart phones sold in a shop per day:
Number of smart phones $(x)$$0$$1$$2$$3$$4$$5$
Probability $(P(x))$$k$$0.3$$0.15$$0.15$$0.1$$2k$

Then $E(x) = ?$

The variance of the random variable $X$ having the following distribution is:
$X = k$$-2$$-1$$0$$1$$2$
$P(X = k)$$\frac{1}{6}$$\frac{1}{6}$$\frac{1}{3}$$\frac{1}{6}$$\frac{1}{6}$

$A$ bakerman sells $5$ types of cakes. Profit due to sale of each type of cake is respectively $Rs \ 2$,$Rs \ 2.5$,$Rs \ 3$,$Rs \ 1.5$ and $Rs \ 1$. The demands for these cakes are $20 \%$,$5 \%$,$10 \%$,$50 \%$ and $15 \%$ respectively. Then the expected profit per cake is:

Let a random variable $X$ take values $\{0, 1, 2, 3\}$ with $P(X=0) = P(X=1) = p$,$P(X=2) = P(X=3) = q$,and $E(X^2) = 2E(X)$. Then the value of $8p - 1$ is:

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