Let $A=\{1,3,7,9,11\}$ and $B=\{2,4,5,7,8,10,12\}$. Then the total number of one-one maps $\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}$, such that $\mathrm{f}(1)+\mathrm{f}(3)=14$, is :

  • [JEE MAIN 2024]
  • A

    $180$

  • B

    $120$

  • C

    $480$

  • D

    $240$

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