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(B) By definition,a relation $R$ is symmetric if $(a, b) \in R$ implies $(b, a) \in R$ for all $a, b \in A$.Given that $R = R^{-1}$.Let $(a, b) \in R$

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Symmetric

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(B) By definition,a relation $R$ is symmetric if $(a, b) \in R$ implies $(b, a) \in R$ for all $a, b \in A$.Given that $R = R^{-1}$.Let $(a, b) \in R$.Since $R = R^{-1}$,it follows that $(a, b) \in R^{-1}$.By the definition of the inverse relation $R^{-1}$,$(a, b) \in R^{-1}$ implies $(b, a) \in R$.Since $(a, b) \in R$ implies $(b, a) \in R$,the relation $R$ is symmetric.

Let $R$ be a relation on a set $A$ such that $R = R^{-1}$,then $R$ is

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