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(B) relation $R$ is defined on a family of sets $X$ such that $A R B$ if $A \cap B = \emptyset$. $1$. Reflexive: For $R$ to be reflexive,$A R A$ must

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Symmetric

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(B) relation $R$ is defined on a family of sets $X$ such that $A R B$ if $A \cap B = \emptyset$. $1$. Reflexive: For $R$ to be reflexive,$A R A$ must hold for all $A \in X$,which means $A \cap A = \emptyset$. This is only true if $A = \emptyset$. Since it does not hold for all $A \in X$,$R$ is not reflexive. $2$. Symmetric: If $A R B$,then $A \cap B = \emptyset$. Since intersection is commutative,$B \cap A = \emptyset$,which implies $B R A$. Thus,$R$ is symmetric. $3$. Transitive: If $A R B$ and $B R C$,then $A \cap B = \emptyset$ and $B \cap C = \emptyset$. This does not necessarily imply $A \cap C = \emptyset$. For example,let $A = \{1\}$,$B = \{2\}$,and $C = \{1\}$. Here $A \cap B = \emptyset$ and $B \cap C = \emptyset$,but $A \cap C = \{1\} 
eq \emptyset$. Thus,$R$ is not transitive. Therefore,the relation is symmetric.

Let $X$ be a family of sets and $R$ be a relation on $X$ defined by '$A$ is disjoint from $B$'. Then $R$ is

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