Let $n(U) = 700,\,n(A) = 200,\,n(B) = 300$ and $n(A \cap B) = 100,$ then $n({A^c} \cap {B^c}) = $

  • A

    $400$

  • B

    $600$

  • C

    $300$

  • D

    $200$

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