Let $A=(4,0)$ and $B=(0,12)$ be two points in the plane. The locus of a point $C(x, y)$ such that the area of $\triangle ABC$ is $18$ sq units is

  • A
    $(y+3x+12)^2=81$
  • B
    $(y+3x+81)^2=12$
  • C
    $(y+3x-12)^2=81$
  • D
    $(y+3x-81)^2=12$

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