(B) Let $S = a + b + c + d + e$. The given system of equations can be written as:$S + a = 6$$S + b = 12$$S + c = 24$$S + d = 48$$S + e = 96$Summing th

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(B) Let $S = a + b + c + d + e$. The given system of equations can be written as:$S + a = 6$$S + b = 12$$S + c = 24$$S + d = 48$$S + e = 96$Summing these five equations,we get:$5S + (a + b + c + d + e) = 6 + 12 + 24 + 48 + 96$$5S + S = 186$$6S = 186$$S = 31$Now,substitute $S = 31$ into the third equation $S + c = 24$:$31 + c = 24$$c = 24 - 31 = -7$Therefore,$|c| = |-7| = 7$.

Competitive Quantitative Aptitude Algebra QUADRATIC EQUATION

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Let $a, b, c, d, e$ be five numbers satisfying the system of equations:
$2a + b + c + d + e = 6$
$a + 2b + c + d + e = 12$
$a + b + 2c + d + e = 24$
$a + b + c + 2d + e = 48$
$a + b + c + d + 2e = 96$
Then $|c|$ is equal to:

A
$6$
B
$7$
C
$8$
D
$25$

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Algebra

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QUADRATIC EQUATION

Find the combined product of $(a^{4}+b^{4})(a^{2}+b^{2})(a+b)(a-b)$.

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Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-16x+63=0$
$II.$ $y^{2}-2y-35=0$

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If the difference between the roots of the equation $x^2 + ax + b = 0$ is equal to the difference between the roots of the equation $x^2 + bx + a = 0$ $(a \ne b)$,then:

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The number of real solutions of the equation $(\frac{3}{2})^x = -x^2 + 5x - 10$ is:

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If one root of the equation $x^2 + px + q = 0$ is the square of the other,then

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Let $a, b, c, d, e$ be five numbers satisfying the system of equations:$2a + b + c + d + e = 6$$a + 2b + c + d + e = 12$$a + b + 2c + d + e = 24$$a + b + c + 2d + e = 48$$a + b + c + d + 2e = 96$Then $|c|$ is equal to:

Similar Questions

Find the combined product of $(a^{4}+b^{4})(a^{2}+b^{2})(a+b)(a-b)$.

Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2}-16x+63=0$$II.$ $y^{2}-2y-35=0$

If the difference between the roots of the equation $x^2 + ax + b = 0$ is equal to the difference between the roots of the equation $x^2 + bx + a = 0$ $(a \ne b)$,then:

The number of real solutions of the equation $(\frac{3}{2})^x = -x^2 + 5x - 10$ is:

If one root of the equation $x^2 + px + q = 0$ is the square of the other,then

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Let $a, b, c, d, e$ be five numbers satisfying the system of equations:
$2a + b + c + d + e = 6$
$a + 2b + c + d + e = 12$
$a + b + 2c + d + e = 24$
$a + b + c + 2d + e = 48$
$a + b + c + d + 2e = 96$
Then $|c|$ is equal to:

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-16x+63=0$
$II.$ $y^{2}-2y-35=0$