Let $\alpha$ and $\beta$ be the roots of the equation $x^2 + x + 1 = 0.$ Then for $y \ne 0$ in $\mathbb{R},$ the determinant $\left| \begin{array}{ccc} y + 1 & \alpha & \beta \\ \alpha & y + \beta & 1 \\ \beta & 1 & y + \alpha \end{array} \right|$ is equal to

  • A
    $y(y^2 - 3)$
  • B
    $y^3 - 1$
  • C
    $y^3$
  • D
    $y(y^2 - 1)$

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