Let $ABC$ be a triangle whose circumcentre is at $P$. If the position vectors of $A, B, C$ and $P$ are $\vec{a}, \vec{b}, \vec{c}$ and $\frac{\vec{a} + \vec{b} + \vec{c}}{4}$ respectively,then the position vector of the orthocentre of this triangle is:

  • A
    $-\left(\frac{\vec{a} + \vec{b} + \vec{c}}{2}\right)$
  • B
    $\vec{a} + \vec{b} + \vec{c}$
  • C
    $\frac{\vec{a} + \vec{b} + \vec{c}}{2}$
  • D
    $\vec{0}$

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