Which region is the least doped in a transistor?

In a transistor output characteristic commonly used in common emitter configuration,the base current $I_{B}$,the collector current $I_{C}$,and the collector-emitter voltage $V_{CE}$ have values of the following orders of magnitude in the active region:

For a given transistor amplifier circuit in $CE$ configuration with $V_{CC} = 1 \text{ V}$,$R_c = 1 \text{ k}\Omega$,$R_b = 100 \text{ k}\Omega$,and $\beta = 100$,the value of the base current $I_b$ is:

The current amplification factor and the collector current in a $CE$ transistor circuit are $100$ and $2.2 \text{ mA}$ respectively. Then the base current is (in $\mu A$)

In the case of a common emitter transistor amplifier,the ratio of collector current to emitter current is $0.96$. Then,the current gain $(\beta)$ of the amplifier is:

In a transistor circuit,the emitter-base circuit of a $n-p-n$ transistor is always