The latent heat of 1 , g of steam is 536 , ca | vedclass

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(A) Given,latent heat $L = 536 \, cal/g$.We know that $1 \, cal = 4.2 \, J$ and $1 \, g = 10^{-3} \, kg$.Substituting these values into the expression

Vedclass · Accepted Answer

$2.25 	imes 10^6$

Vedclass · Answer

(A) Given,latent heat $L = 536 \, cal/g$.We know that $1 \, cal = 4.2 \, J$ and $1 \, g = 10^{-3} \, kg$.Substituting these values into the expression:$L = 536 	imes \frac{4.2 \, J}{10^{-3} \, kg}$$L = 536 	imes 4.2 	imes 10^3 \, J/kg$$L = 2251.2 	imes 10^3 \, J/kg \approx 2.25 	imes 10^6 \, J/kg$.Therefore,the correct option is $A$.

The latent heat of $1 \, g$ of steam is $536 \, cal/g$. Its value in $J/kg$ is:

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