It takes 24 , s for a train travelling at 93 | vedclass

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(A) Relative speed of the two trains $= 93 + 51 = 144 \, km/h$.Converting to $m/s$: $144 	imes \frac{5}{18} = 40 \, m/s$.Let the length of the first

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$1065$

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(A) Relative speed of the two trains $= 93 + 51 = 144 \, km/h$.Converting to $m/s$: $144 	imes \frac{5}{18} = 40 \, m/s$.Let the length of the first train be $L$. The length of the second train is $\frac{L}{2}$.Total distance covered while crossing $= L + \frac{L}{2} = \frac{3L}{2}$.Total distance $= 	ext{Relative speed} 	imes 	ext{Time} = 40 	imes 24 = 960 \, m$.So,$\frac{3L}{2} = 960 \implies L = 960 	imes \frac{2}{3} = 640 \, m$.The first train passes a bridge of length $x$ in $66 \, s$ at a speed of $93 \, km/h$.Speed of the train in $m/s = 93 	imes \frac{5}{18} = \frac{31 	imes 5}{6} = \frac{155}{6} \, m/s$.Distance covered $= 	ext{Length of train} + 	ext{Length of bridge} = 640 + x$.$640 + x = \frac{155}{6} 	imes 66 = 155 	imes 11 = 1705$.$x = 1705 - 640 = 1065 \, m$.

It takes $24 \, s$ for a train travelling at $93 \, km/h$ to cross entirely another train half its length travelling in the opposite direction at $51 \, km/h$. It passes a bridge in $66 \, s$. What is the length of the bridge in meters?

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