It is estimated that each cm^2 of Earth recei | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The solar constant $S$ is given as $2 	ext{ cal cm}^{-2} 	ext{ min}^{-1}$.To convert this into $S.I.$ units ($W/m^2$ or $J s^{-1} m^{-2}$):$1

Vedclass · Accepted Answer

$1.4 	ext{ kW m}^{-2}$

Vedclass · Answer

(D) The solar constant $S$ is given as $2 	ext{ cal cm}^{-2} 	ext{ min}^{-1}$.To convert this into $S.I.$ units ($W/m^2$ or $J s^{-1} m^{-2}$):$1 	ext{ calorie} = 4.184 	ext{ J}$$1 	ext{ cm}^2 = 10^{-4} 	ext{ m}^2$$1 	ext{ minute} = 60 	ext{ s}$Substituting these values:$S = \frac{2 	imes 4.184 	ext{ J}}{10^{-4} 	ext{ m}^2 	imes 60 	ext{ s}}$$S = \frac{8.368}{60 	imes 10^{-4}} 	ext{ W/m}^2$$S = \frac{8.368}{0.006} 	ext{ W/m}^2 \approx 1394.6 	ext{ W/m}^2$Rounding this value,we get approximately $1.4 	ext{ kW/m}^2$ or $1.4 	ext{ kW m}^{-2}$.

List-$I$	List-$II$
$A$. Spring constant	$I$. $ML^2 T^{-2} K^{-1}$
$B$. Thermal conductivity	$II$. $ML^0 T^{-2}$
$C$. Boltzmann constant	$III$. $ML^2 T^{-3} A^{-2}$
$D$. Inductive reactance	$IV$. $MLT^{-3} K^{-1}$

It is estimated that each $cm^2$ of Earth receives about $2 \text{ calorie}$ of heat energy per minute from the Sun. This is called the solar constant. The value of the solar constant in $S.I.$ units is:

Similar Questions

Which one has dimensions different from the remaining three?

The ratio $\left(\frac{E}{W}\right)$ of relative strength of electromagnetic force $(E)$ to weak nuclear force $(W)$ is,

In an electromagnetic system,a quantity defined as the ratio of electric dipole moment and magnetic dipole moment has dimensions of $[M^P L^Q T^R A^S]$. The values of $P$ and $Q$ are:

The two principal thrusts in physics are

Vedclass Test Series

Exam Paper Generator

Online Exam Module