Isobutene,in the presence of H_2SO_4,forms a | vedclass

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(B) The dimerization of isobutene in the presence of $H_2SO_4$ proceeds via the formation of a tert-butyl carbocation. This carbocation attacks anothe

Vedclass · Accepted Answer

$CH_3-C(CH_3)_2-CH_2-C(CH_3)=CH_2$

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(B) The dimerization of isobutene in the presence of $H_2SO_4$ proceeds via the formation of a tert-butyl carbocation. This carbocation attacks another molecule of isobutene to form a larger carbocation intermediate: $(CH_3)_3C-CH_2-C^+(CH_3)_2$. This intermediate can lose a proton to form two isomeric alkenes. Due to the steric hindrance caused by the bulky tert-butyl group,the removal of a proton from the terminal methyl group is favored,leading to the formation of the less substituted (Hoffmann) alkene as the major product. The major product is $2,4,4-trimethylpent-1-ene$,which is represented by the structure $CH_3-C(CH_3)_2-CH_2-C(CH_3)=CH_2$.

Isobutene,in the presence of $H_2SO_4$,forms a mixture of two isomeric alkenes $(C_8H_{16})$. The major alkene is

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