Instead of dividing $391$ cookies among $3$ children $A$, $B,C$ in the ratio $\frac{1}{5}: \frac{1}{4}: \frac{1}{8},$ it was divided in to the ratio $5: 4: 8 .$ Who gains the most and how many?
Instead of dividing $391$ cookies among $3$ children $A$, $B,C$ in the ratio $\frac{1}{5}: \frac{1}{4}: \frac{1}{8},$ it was divided in to the ratio $5: 4: 8 .$ Who gains the most and how many?
- A
$A, 21$ cookies
- B
$B, 78$ cookies
- C
$C, 99$ cookies
- D
$C, 78$ cookies
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In these questions, two equations mabered $I$ and $II$ are given. You have to solve both the equations and mark the appropriate option.
$I.$ $2 x^{2}-11 x+15=0$
$II$. $2 y^{2}-11 y+14=0$
In these questions, two equations mabered $I$ and $II$ are given. You have to solve both the equations and mark the appropriate option.
$I.$ $2 x^{2}-11 x+15=0$
$II$. $2 y^{2}-11 y+14=0$