A man sells each of his 2 articles for Rs. 99 | vedclass

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(B) Cost Price $(CP)$ of the $1$st article $= \frac{99}{1 + 0.10} = \frac{99}{1.10} = Rs. 90$ (Profit of $10 \%$).Cost Price $(CP)$ of the $2$nd artic

Vedclass · Accepted Answer

$4 \frac{4}{19}$

Vedclass · Answer

(B) Cost Price $(CP)$ of the $1$st article $= \frac{99}{1 + 0.10} = \frac{99}{1.10} = Rs. 90$ (Profit of $10 \%$).Cost Price $(CP)$ of the $2$nd article $= \frac{99}{1 - 0.01} = \frac{99}{0.99} = Rs. 100$ (Loss of $1 \%$).Total $CP$ of both articles $= 90 + 100 = Rs. 190$.Total Selling Price $(SP)$ of both articles $= 99 + 99 = Rs. 198$.Total Profit $= 198 - 190 = Rs. 8$.Profit $\%$ $= \left( \frac{	ext{Total Profit}}{	ext{Total } CP} ight) 	imes 100 = \left( \frac{8}{190} ight) 	imes 100 = \frac{80}{19} = 4 \frac{4}{19} \%$.

$A$ man sells each of his $2$ articles for $Rs. 99$. On one he gains $10 \%$ and on the other he incurs a loss of $1 \%$. What is his total gain in $\%$ in the entire transaction?

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