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Question

(D) The side of the square plot is $a = 28\, m$.The area of the square plot is $a^2 = 28^2 = 784\, m^2$.The diameter of the circular garden is $d = 28

Vedclass · Accepted Answer

$168$

Vedclass · Answer

(D) The side of the square plot is $a = 28\, m$.The area of the square plot is $a^2 = 28^2 = 784\, m^2$.The diameter of the circular garden is $d = 28\, m$,so the radius is $r = \frac{d}{2} = 14\, m$.The area of the circular garden is $\pi r^2 = \frac{22}{7} 	imes 14 	imes 14 = 22 	imes 2 	imes 14 = 616\, m^2$.The area of the space left out is the difference between the area of the square and the area of the circle:Area left out $= 784\, m^2 - 616\, m^2 = 168\, m^2$.

Inside a square plot,a circular garden is developed which exactly fits in the square plot and the diameter of the garden is equal to the side of the square plot which is $28\, m$. What is the area of the space left out in the square plot after developing the garden? (in $m^2$)

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