Insert a rational number and an irrational number between the following:
$\frac{-2}{5}$ and $\frac{1}{2}$
Insert a rational number and an irrational number between the following:
$\frac{-2}{5}$ and $\frac{1}{2}$
$\frac{-2}{5}=-0.4$ and $\frac{1}{2}=0.5$
Now, $0$ is a rational number between $-0.4$ and $0.5$
i.e., $0$ is a rational number lying between $\frac{-2}{5}$ and $\frac{1}{2}$
Again, $0.131131113 ....$ is a non - terminating and non - recurring decimal which lies between $-0.4$ and $0.5 .$ Hence, $0.131131113 ...$ is an irrational number lying between $\frac{-2}{5}$ and $\frac{1}{2}$.
Similar Questions
Is $\sqrt{8^{2}+15^{2}}$ a rational number or an irrational number ?
Is $\sqrt{8^{2}+15^{2}}$ a rational number or an irrational number ?
For each question, select the proper option from four options given, to make the statement true : (Final answer only)
$(\sqrt{5}+3)^{2}$ is a $/$ an $\ldots \ldots \ldots$ number.
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Express $0.7 \overline{39}$ in the form $\frac{P}{q} ;$ where $p$ and $q$ are integers and $q \neq 0$
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Simplify:
$\frac{9^{\frac{1}{3}} \times 27^{-\frac{1}{2}}}{3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}}$
Simplify:
$\frac{9^{\frac{1}{3}} \times 27^{-\frac{1}{2}}}{3^{\frac{1}{6}} \times 3^{-\frac{2}{3}}}$