In the year 2008,5000 students were admitted | vedclass

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(A) The initial number of students admitted in $2008$ $(P)$ is $5000$.The rate of increase $(r)$ is $24\%$ per year.The time period $(n)$ from $2008$

Vedclass · Accepted Answer

$7688$

Vedclass · Answer

(A) The initial number of students admitted in $2008$ $(P)$ is $5000$.The rate of increase $(r)$ is $24\%$ per year.The time period $(n)$ from $2008$ to $2010$ is $2010 - 2008 = 2$ years.Since the number of students increases at a constant percentage rate,we use the compound growth formula: $A = P \left(1 + \frac{r}{100}ight)^n$.Substituting the values: $A = 5000 \left(1 + \frac{24}{100}ight)^2$.$A = 5000 	imes (1.24)^2$.$A = 5000 	imes 1.5376$.$A = 7688$.Therefore,the number of students admitted in the year $2010$ will be $7688$.

In the year $2008$,$5000$ students were admitted to a college. It is found that the number of students admitted is constantly increasing by $24\%$ per year. How many students will be admitted to the college in the year $2010$?

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