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(B) The relationship between the electric field $(E)$ and the potential $(V)$ is given by the formula $E_x = -\frac{dV}{dx}$.This means the magnitude

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$2$

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(B) The relationship between the electric field $(E)$ and the potential $(V)$ is given by the formula $E_x = -\frac{dV}{dx}$.This means the magnitude of the $x$-component of the electric field,$|E_x|$,is equal to the absolute value of the slope of the $V-X$ graph,i.e.,$|E_x| = |\frac{dV}{dx}|$.To find the region where the magnitude of the electric field is maximum,we need to identify the region where the slope of the $V-X$ graph is steepest (i.e.,has the largest absolute value).Looking at the graph:- In regions $1$ and $4$,the potential is constant,so the slope is $0$,which means $E_x = 0$.- In regions $2$ and $3$,the potential changes with distance,so the slope is non-zero.- Comparing the steepness of the lines in regions $2$ and $3$,the line in region $2$ is much steeper than the line in region $3$.Therefore,the magnitude of the slope is maximum in region $2$,which implies the magnitude of the electric field is maximum in region $2$.

In which region is the magnitude of the $x$-component of the electric field maximum,if the potential $(V)$ versus distance $(X)$ graph is as shown?

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