In which quadrant or on which axis do each of the points $(-2, 4)$,$(3, -1)$,$(-1, 0)$,$(1, 2)$ and $(-3, -5)$ lie? Verify your answer by locating them on the Cartesian plane.

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(N/A) For the point $(-2, 4)$,the abscissa ($x$-coordinate) is negative and the ordinate ($y$-coordinate) is positive. Since $(-, +)$ belongs to the $2nd$ quadrant,$(-2, 4)$ lies in the $2nd$ quadrant.
For the point $(3, -1)$,the abscissa is positive and the ordinate is negative. Since $(+, -)$ belongs to the $4th$ quadrant,$(3, -1)$ lies in the $4th$ quadrant.
For the point $(-1, 0)$,the ordinate is $0$. Any point with an ordinate of $0$ lies on the $x$-axis. Since the abscissa is negative,$(-1, 0)$ lies on the negative $x$-axis.
For the point $(1, 2)$,both the abscissa and the ordinate are positive. Since $(+, +)$ belongs to the $1st$ quadrant,$(1, 2)$ lies in the $1st$ quadrant.
For the point $(-3, -5)$,both the abscissa and the ordinate are negative. Since $(-, -)$ belongs to the $3rd$ quadrant,$(-3, -5)$ lies in the $3rd$ quadrant.
These points are plotted in the Cartesian plane as shown in the figure: $A(-2, 4)$,$B(3, -1)$,$C(-1, 0)$,$D(1, 2)$,and $E(-3, -5)$.

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(Street Plan) : $A$ city has two main roads which cross each other at the centre of the city. These two roads are along the North-South direction and East-West direction. All the other streets of the city run parallel to these roads and are $200 \,m$ apart. There are $5$ streets in each direction. Using $1 \,cm = 200 \,m$,draw a model of the city on your notebook. Represent the roads/streets by single lines. There are many cross-streets in your model. $A$ particular cross-street is made by two streets,one running in the North-South direction and another in the East-West direction. Each cross-street is referred to in the following manner: If the $2^{nd}$ street running in the North-South direction and $5^{th}$ in the East-West direction meet at some crossing,then we will call this cross-street $(2, 5).$ Using this convention,find:
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