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(B) $1$. For $XeOF_4$: Central atom $Xe$ has $8$ valence electrons. It forms $4$ $\sigma$-bonds with $F$ atoms and $1$ $\sigma$-bond with $O$ atom (to

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$XeOF_4, XeF_5^{\oplus}$

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(B) $1$. For $XeOF_4$: Central atom $Xe$ has $8$ valence electrons. It forms $4$ $\sigma$-bonds with $F$ atoms and $1$ $\sigma$-bond with $O$ atom (total $5$ $\sigma$-bonds). It has $1$ lone pair. Shape is square pyramidal. Total (lone pair + $\sigma$-bond) = $1 + 5 = 6$.$2$. For $XeF_5^{\oplus}$: Central atom $Xe$ has $7$ valence electrons (after losing $1$). It forms $5$ $\sigma$-bonds with $F$ atoms. It has $1$ lone pair. Shape is square pyramidal. Total (lone pair + $\sigma$-bond) = $1 + 5 = 6$.$3$. Since both have the same shape (square pyramidal) and the same total number of lone pairs and $\sigma$-bonds $(6)$,the correct pair is $XeOF_4$ and $XeF_5^{\oplus}$.

Which of the following pairs have the same shape and the same total number of lone pairs and $\sigma$-bond pairs on the central atom?

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