In which of the following coordination entiti | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In all the given complexes,the central metal ion is $Co^{3+}$ ($d^6$ configuration). Since the metal ion and its oxidation state are identical,the

Vedclass · Accepted Answer

$[Co(CN)_6]^{3-}$

Vedclass · Answer

(A) In all the given complexes,the central metal ion is $Co^{3+}$ ($d^6$ configuration). Since the metal ion and its oxidation state are identical,the magnitude of the crystal field splitting energy $(\Delta_o)$ depends solely on the nature of the ligands. According to the spectrochemical series,the strength of ligands follows the order: $CN^- > NH_3 > H_2O > C_2O_4^{2-}$. $CN^-$ is the strongest field ligand among the given options,which causes the largest splitting of $d$-orbitals. Therefore,the magnitude of $\Delta_o$ is maximum in $[Co(CN)_6]^{3-}$.

In which of the following coordination entities the magnitude of $\Delta_o$ ($CFSE$ in octahedral field) will be maximum? (Atomic Number of $Co = 27$)

Similar Questions

In which of the following,complex ions are not in correct order with respect to their magnitude of crystal field splitting?

The degenerate orbitals of $[Cr(H_2O)_6]^{3+}$ are

The $CFSE$ for $[CoCl_6]^{4-}$ complex is $18000 \ cm^{-1}$. The $\Delta_t$ for $[CoCl_4]^{2-}$ will be ........... $cm^{-1}$.

Number of complexes with an even number of electrons in $t_{2g}$ orbitals is -
$[Fe(H_2O)_6]^{2+}, [Co(H_2O)_6]^{2+}, [Co(H_2O)_6]^{3+}, [Cu(H_2O)_6]^{2+}, [Cr(H_2O)_6]^{2+}$

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module