In thermodynamics,for an isochoric process,wh | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) An isochoric process is defined as a process where the volume of the system remains constant $(dV = 0)$.Since work done $dW = P dV$,if $dV = 0$,th

Vedclass · Accepted Answer

Energy exchanged is used to do work and also to change internal energy

Vedclass · Answer

(A) An isochoric process is defined as a process where the volume of the system remains constant $(dV = 0)$.Since work done $dW = P dV$,if $dV = 0$,then $dW = 0$. Thus,no work is done in the process.According to the first law of thermodynamics,$dQ = dU + dW$. Since $dW = 0$,the heat exchanged $(dQ)$ is entirely used to change the internal energy $(dU)$ of the system.Therefore,statement $(A)$ is incorrect because energy exchanged is not used to do work.

In thermodynamics,for an isochoric process,which one of the following statements is $INCORRECT$?

Similar Questions

$A$ monoatomic gas $(\gamma = 5/3)$ expands at constant pressure when heat is supplied. What percentage of the heat supplied is converted into internal energy and work, respectively?

In an isobaric process of an ideal gas, the ratio of work done by the system $(W)$ during the expansion and the heat exchanged $(Q)$ is $(\gamma = \frac{C_p}{C_v})$

When $1 \, mol$ of nitrogen gas is heated at constant pressure at room temperature,it is supplied with $1163.4 \, J$ of energy. The increase in temperature is ....... $K$ $(R = 8.31 \, J \, mol^{-1} \, K^{-1})$.

For an isochoric process,if $T_1 = 27 \, ^\circ C$ and $T_2 = 127 \, ^\circ C$,then $P_1 / P_2 = \dots$

Which one of the following equations specifies an isobaric process?
$[Q=$ heat supplied; $\Delta P, \Delta V$ and $\Delta T$ are change in pressure,volume,and temperature respectively.]

Vedclass Test Series

Exam Paper Generator

Online Exam Module