In the usual notations,$Z - M = \ldots \ldots \ldots \quad (M - \bar{x})$
- A$4$
- B$3$
- C$1$
- D$2$
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Similar Questions
Consider the following frequency distribution:
Class $0-5$ $6-11$ $12-17$ $18-23$ $24-29$ Frequency $13$ $10$ $15$ $8$ $11$
The upper limit of the median class is
| Class | $0-5$ | $6-11$ | $12-17$ | $18-23$ | $24-29$ |
| Frequency | $13$ | $10$ | $15$ | $8$ | $11$ |
The upper limit of the median class is
Medium
View SolutionThe mean of the following data is $55.5$ and the total frequency is $20$. Find the missing frequencies $x$ and $y$.
Class $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $3$ $x$ $7$ $7$ $y$
| Class | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $3$ | $x$ | $7$ | $7$ | $y$ |
Medium
View SolutionIn the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$h = \ldots \ldots \ldots$
Easy
View SolutionFind the mean,median,and mode of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ Frequency $5$ $27$ $58$ $20$ $10$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ |
|---|---|---|---|---|---|
| Frequency | $5$ | $27$ | $58$ | $20$ | $10$ |
Medium
View SolutionFind the median of the following frequency distribution:
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $2$ $6$ $8$ $16$ $20$ $18$ $16$ $14$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $2$ | $6$ | $8$ | $16$ | $20$ | $18$ | $16$ | $14$ |
Difficult
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