In the reaction LiH + AlH_3 rightarrow LiAlH_ | vedclass

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(A) In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,the $AlH_3$ molecule has an incomplete octet around the central $Al$ atom,making it electron-def

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Lewis acid and Lewis base

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(A) In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,the $AlH_3$ molecule has an incomplete octet around the central $Al$ atom,making it electron-deficient and thus a Lewis acid. $LiH$ contains the hydride ion $H^-$,which has a lone pair of electrons that it can donate to the $Al$ atom in $AlH_3$. Since $LiH$ acts as an electron pair donor,it functions as a Lewis base. Therefore,$AlH_3$ is a Lewis acid and $LiH$ is a Lewis base.

In the reaction $LiH + AlH_3 \rightarrow LiAlH_4$,$AlH_3$ and $LiH$ act as

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