The correct order of IE_2 (second ionization | vedclass

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Question

(C) The second ionization enthalpy $(IE_2)$ corresponds to the energy required to remove an electron from a unipositive ion $(M^+ \rightarrow M^{2+} +

Vedclass · Accepted Answer

$Ne > O > F > N$

Vedclass · Answer

(C) The second ionization enthalpy $(IE_2)$ corresponds to the energy required to remove an electron from a unipositive ion $(M^+ \rightarrow M^{2+} + e^-)$.Electronic configurations of the corresponding unipositive ions are:$N^+: 1s^2 2s^2 2p^2$$O^+: 1s^2 2s^2 2p^3$$F^+: 1s^2 2s^2 2p^4$$Ne^+: 1s^2 2s^2 2p^5$As we move from $N^+$ to $Ne^+$,the effective nuclear charge increases,which generally increases $IE_2$.However,$N^+$ has a stable half-filled $2p$ subshell,and $Ne^+$ has a stable configuration. Comparing the values,the order is $Ne > O > F > N$.

The correct order of $IE_2$ (second ionization enthalpy) is:

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