In the network shown in the adjoining figure, | vedclass

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(D) The given circuit can be simplified by identifying series and parallel combinations.$1$. The top part of the circuit forms a delta-like structure.

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$(8/7)\,\Omega$

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(D) The given circuit can be simplified by identifying series and parallel combinations.$1$. The top part of the circuit forms a delta-like structure. By simplifying the internal branches,we can reduce the network step-by-step.$2$. The two resistors in the middle branch are in series with the top resistor,forming a triangle. The equivalent resistance of the top section simplifies to $(2/3)\,\Omega$ in series with two $1\,\Omega$ resistors,totaling $(1 + 2/3 + 1) = (8/3)\,\Omega$.$3$. The bottom branch consists of two $1\,\Omega$ resistors in series,which is $2\,\Omega$.$4$. Now,the circuit is reduced to two parallel branches: one with $(8/3)\,\Omega$ and the other with $2\,\Omega$.$5$. The effective resistance $R_{AB}$ is given by the parallel formula: $1/R_{AB} = 1/(8/3) + 1/2 = 3/8 + 1/2 = (3+4)/8 = 7/8$.$6$. Therefore,$R_{AB} = 8/7\,\Omega$.

In the network shown in the adjoining figure,each resistance is $1\,\Omega$. The effective resistance between $A$ and $B$ is

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