In the molecule CH_3-C equiv C-CH=CH_2,the ma | vedclass

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(C) The structure of the molecule is $CH_3-C \equiv C-CH=CH_2$.In this molecule,the carbon atoms involved in the triple bond $(C \equiv C)$ are $sp$ h

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$4$

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(C) The structure of the molecule is $CH_3-C \equiv C-CH=CH_2$.In this molecule,the carbon atoms involved in the triple bond $(C \equiv C)$ are $sp$ hybridized,which means they have a linear geometry ($180^{\circ}$ bond angle).The carbon atom adjacent to the triple bond (the $CH$ group) is $sp^2$ hybridized,but the bond angle around the $C \equiv C-C$ linkage allows for a linear arrangement of the atoms involved in the triple bond and the adjacent carbon.Specifically,the sequence $CH_3-C \equiv C-CH$ involves four carbon atoms that lie in a linear arrangement due to the $sp$ hybridization of the alkyne carbons.Therefore,the maximum number of carbon atoms arranged linearly is $4$.

In the molecule $CH_3-C \equiv C-CH=CH_2$,the maximum number of carbon atoms arranged linearly is

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