The product obtained in this reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction involves the terminal alkyne $Ph-C \equiv C-H$ reacting with $I_2$ in the presence of a base (morpholine).$1$. The base (morpholine)

Vedclass · Accepted Answer

$Ph-C \equiv C-I$

Vedclass · Answer

(A) The reaction involves the terminal alkyne $Ph-C \equiv C-H$ reacting with $I_2$ in the presence of a base (morpholine).$1$. The base (morpholine) abstracts the acidic terminal proton from the alkyne to form an acetylide anion: $Ph-C \equiv C^-$.$2$. The acetylide anion then acts as a nucleophile and attacks the iodine molecule $(I-I)$,displacing an iodide ion $(I^-)$.$3$. This results in the formation of the iodoalkyne product: $Ph-C \equiv C-I$.

Similar Questions

Which of the following reactions forms an aldehyde as a product?

The number and type of bonds between two carbon atoms in $CaC_2$ are

The final major product obtained in the following sequence of reaction is

$CH_3-C \equiv C-CH_3 \xrightarrow{\text{Cold } KMnO_4} (A)$
Product $(A)$ is:

Which of the following reactions will yield $2, 2-$dibromopropane?

Vedclass Test Series

Exam Paper Generator

Online Exam Module