In the graph of the function sqrt{3} sin x + | vedclass

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(B) The function is given by $f(x) = \sqrt{3} \sin x + \cos x$.To find the maximum distance from the $x$-axis,we need to find the maximum absolute val

Vedclass · Accepted Answer

$2$

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(B) The function is given by $f(x) = \sqrt{3} \sin x + \cos x$.To find the maximum distance from the $x$-axis,we need to find the maximum absolute value of the function,which is the amplitude of the expression $a \sin x + b \cos x$.The amplitude is given by $\sqrt{a^2 + b^2}$.Here,$a = \sqrt{3}$ and $b = 1$.Maximum distance $= \sqrt{(\sqrt{3})^2 + (1)^2} = \sqrt{3 + 1} = \sqrt{4} = 2$.Thus,the maximum distance of a point from the $x$-axis is $2$.

In the graph of the function $\sqrt{3} \sin x + \cos x$,the maximum distance of a point from the $x$-axis is:

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