In the given reaction,identify the final product.

The correct option$(s)$ for the following sequence of reactions is(are):
$(A)$ $Q = KNO_2, W = LiAlH_4$
$(B)$ $R =$ benzenamine,$V = KCN$
$(C)$ $Q = AgNO_2, R =$ phenylmethanamine
$(D)$ $W = LiAlH_4, V = AgCN$

Identify the incorrect statements.

$A$ colourless substance $'A'$ $(C_6H_7N)$ is sparingly soluble in water and gives a water-soluble compound $'B'$ on treating with mineral acid. On reacting with $CHCl_3$ and alcoholic potash,$'A'$ produces an obnoxious smell due to the formation of compound $'C'$. Reaction of $'A'$ with benzenesulphonyl chloride gives compound $'D'$ which is soluble in alkali. With $NaNO_2$ and $HCl$,$'A'$ forms compound $'E'$ which reacts with phenol in an alkaline medium to give an orange dye $'F'$. Identify compounds $'A'$ to $'F'$.

Consider the following sequence of reactions:
Chlorobenzene $\xrightarrow[ii) CO_2, H_3O^{+}]{i) Mg, \text{dry ether}} \text{Benzoic acid}$ $\xrightarrow{NH_3, \Delta} \text{Benzamide (A)}$ $\xrightarrow{Br_2, NaOH} \text{Aniline (B)}$
$11.25 \ mg$ of chlorobenzene will produce $.......... \times 10^{-1} \ mg$ of product $B$.
(Consider the reactions result in complete conversion.)
[Given molar mass of $C, H, O, N$ and $Cl$ as $12, 1, 16, 14$ and $35.5 \ g \ mol^{-1}$ respectively]

Give the structures of $A$,$B$ and $C$ in the following reactions:
$(i)$ $CH_3CH_2I$ $\xrightarrow{NaCN} A$ $\xrightarrow[Partial\,hydrolysis]{OH^{-}} B$ $\xrightarrow{NaOH+Br_2} C$
$(ii)$ $C_6H_5N_2Cl$ $\xrightarrow{CuCN} A$ $\xrightarrow{H_2O/H^{+}} B$ $\xrightarrow[\Delta]{NH_3} C$
$(iii)$ $CH_3CH_2Br$ $\xrightarrow{KCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow[0\ ^oC]{HNO_2} C$
$(iv)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{NaNO_2+HCl} B$ $\xrightarrow[\Delta]{H_2O/H^{+}} C$
$(v)$ $CH_3COOH$ $\xrightarrow[\Delta]{NH_3} A$ $\xrightarrow{NaOBr} B$ $\xrightarrow{NaNO_2/HCl} C$
$(vi)$ $C_6H_5NO_2$ $\xrightarrow{Fe/HCl} A$ $\xrightarrow[273\ K]{HNO_2} B$ $\xrightarrow{C_6H_5OH} C$