In the given reaction,[X] will be: | vedclass

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(C) The reaction involves the addition of $HBr$ to the double bond of cyclohex$-1-$ene$-1-$carboxylic acid. According to Markovnikov's rule,the electr

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$1-$Bromocyclohexane$-1-$carboxylic acid

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(C) The reaction involves the addition of $HBr$ to the double bond of cyclohex$-1-$ene$-1-$carboxylic acid. According to Markovnikov's rule,the electrophile $H^+$ adds to the carbon atom of the double bond that has more hydrogen atoms,and the nucleophile $Br^-$ adds to the other carbon atom. In cyclohex$-1-$ene$-1-$carboxylic acid,the double bond is between $C_1$ and $C_2$. The $C_1$ atom is attached to the $-COOH$ group and has no hydrogen atoms,while the $C_2$ atom has one hydrogen atom. Therefore,$H^+$ adds to $C_2$ and $Br^-$ adds to $C_1$. This results in the formation of $1$-bromocyclohexane-$1$-carboxylic acid as the product $[X]$.

In the given reaction,$[X]$ will be:

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