In the given reaction: $CH_3-CHCl-COOH \xrightarrow[(ii) H_2O]{(i) NH_3 (1 \text{ mole})} [X]$. Product $[X]$ will be:

  • A
    $\alpha$-Amino acid
  • B
    $\alpha$-Aminoamide
  • C
    $\beta$-Amino acid
  • D
    $\beta$-Aminoamide

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