In the given figure net magnetic field at $O$ will be
$\frac{{2{\mu _0}i}}{{3\pi a}}\sqrt {4 - {\pi ^2}} $
$\frac{{{\mu _0}i}}{{3\pi a}}\sqrt {4 + {\pi ^2}} $
$\frac{{2{\mu _0}i}}{{3\pi {a^2}}}\sqrt {4 + {\pi ^2}} $
$\frac{{2{\mu _0}i}}{{3\pi a}}\sqrt {(4 - {\pi ^2})} $
When the current flowing in a circular coil is doubled and the number of turns of the coil in it is halved, the magnetic field at its centre will become
Two thick wires and two thin wires, all of the same materials and same length form a square in the three different ways $P$, $Q$ and $R$ as shown in fig with current connection shown, the magnetic field at the centre of the square is zero in cases
Two circular coils $P$ and $Q$of $100$ turns each have same radius of $\pi \mathrm{cm}$. The currents in $\mathrm{P}$ and $\mathrm{R}$ are $1 \mathrm{~A}$ and $2 \mathrm{~A}$ respectively. $\mathrm{P}$ and $\mathrm{Q}$ are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is $\sqrt{\mathrm{x}} \mathrm{mT}$, where X=___.
$\left[\text { Use } \mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}\right]$
The ratio of the magnetic field at the centre of a current carrying coil of the radius $a$ and at a distance ‘$a$’ from centre of the coil and perpendicular to the axis of coil is
Find magnetic field at point $P$ in given diagram.