In the given circuit,the value of current $I_{L}$ will be in $mA$. (When $R_{L} = 1 \, k\Omega$)

Take the breakdown voltage of the zener diode used in the given circuit as $6\, V$. For the input voltage shown in the figure below, the time variation of the output voltage is: (Graphs drawn are schematic and not to scale)

For the given circuit (shown in part $(A)$),the time-dependent input voltage $v_{in}(t)$ and the corresponding output voltage $v_{o}(t)$ are shown in part $(B)$ and part $(C)$,respectively. Identify the components that are used in the circuit between points $X$ and $Y$.

$A$ Zener diode of breakdown voltage $V_{Z} = 8\,V$ and maximum Zener current $I_{ZM} = 10\,mA$ is subjected to an input voltage $V_{i} = 10\,V$ with a series resistance $R = 100\,\Omega$. In the given circuit,$R_{L}$ represents the variable load resistance. The ratio of the maximum and minimum value of $R_{L}$ is

$A$ Zener diode in the circuit shown has a knee current of $5\,mA$ and a maximum allowed power dissipation of $300\,mW$. What are the minimum and maximum load currents that can be drawn safely from the circuit, keeping the output voltage $V_0$ constant at $6\,V$?

$A$ diode has Zener voltage of $10 \text{ V}$ and maximum power dissipation of $0.5 \text{ W}$. The minimum resistance to be used in series with this diode for safety when it is connected to a $25 \text{ V}$ power supply is . . . . . . $\Omega$.