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(B) The circuit in $(A)$ consists of an ideal diode and a Zener diode connected in series,which acts as a voltage clipper. From part $(C)$,the output

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(B) The circuit in $(A)$ consists of an ideal diode and a Zener diode connected in series,which acts as a voltage clipper. From part $(C)$,the output voltage $v_{o}(t)$ is clipped at $+5 	ext{ V}$ and $-5 	ext{ V}$ (since the Zener breakdown voltage $V_Z = 5 	ext{ V}$). The input voltage $v_{in}(t)$ (part $B$) is a sine wave with an amplitude of $20 	ext{ V}$. When the input is positive,the Zener diode operates in the breakdown region,clamping the output to $+5 	ext{ V}$. When the input is negative,the ideal diode is forward-biased and the Zener diode is reverse-biased,clamping the output to $-5 	ext{ V}$. Thus,the circuit between points $X$ and $Y$ consists of an ideal diode and a Zener diode connected in series. Among the given options,the configuration that represents this behavior is the series combination of two diodes (one ideal and one Zener,though the diagram in option $B$ shows two standard diodes,the question implies identifying the series combination of the two components shown in the circuit). However,based on the standard interpretation of such problems,the correct arrangement is the series connection of the two diodes.

For the given circuit (shown in part $(A)$),the time-dependent input voltage $v_{in}(t)$ and the corresponding output voltage $v_{o}(t)$ are shown in part $(B)$ and part $(C)$,respectively. Identify the components that are used in the circuit between points $X$ and $Y$.

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