In the gaps of a meter bridge,two unknown resistances $A$ and $B$ are connected. $A$ null point is obtained when the wire is divided in the ratio $3:4$. When each resistance is increased by $40 \Omega$,the null point divides the wire in the ratio $7:8$. The values of resistances $A$ and $B$ are respectively:

  • A
    $20 \Omega, 30 \Omega$
  • B
    $30 \Omega, 40 \Omega$
  • C
    $40 \Omega, 60 \Omega$
  • D
    $60 \Omega, 80 \Omega$

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