In an experiment to determine the temperature | vedclass

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(C) Standard resistance,$S=4 \ \Omega$.At $t_1=0^{\circ} C$,the balancing length is $l_1=50 \ cm$.The resistance of the coil $X$ is given by $R_1 = \f

Vedclass · Accepted Answer

$0.005^{\circ} C^{-1}$

Vedclass · Answer

(C) Standard resistance,$S=4 \ \Omega$.At $t_1=0^{\circ} C$,the balancing length is $l_1=50 \ cm$.The resistance of the coil $X$ is given by $R_1 = \frac{l_1}{100-l_1} 	imes S$.$R_1 = \frac{50}{100-50} 	imes 4 = \frac{50}{50} 	imes 4 = 4 \ \Omega$.At $t_2=100^{\circ} C$,the balancing length is $l_2=60 \ cm$.The resistance of the coil $X$ is $R_2 = \frac{l_2}{100-l_2} 	imes S$.$R_2 = \frac{60}{100-60} 	imes 4 = \frac{60}{40} 	imes 4 = 6 \ \Omega$.The temperature coefficient of resistance $\alpha$ is given by $\alpha = \frac{R_2 - R_1}{R_1(t_2 - t_1)}$.$\alpha = \frac{6 - 4}{4(100 - 0)} = \frac{2}{400} = 0.005^{\circ} C^{-1}$.

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