(A) In the formula for calculating the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$,the term $l

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(A) In the formula for calculating the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$,the term $l$ represents the lower limit of the modal class. The modal class is the class interval with the highest frequency.

Class 10 Mathematics Statistics Mix Examples - Statistics

Easy

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$l = \ldots \ldots \ldots$

A
lower limit of the modal class
B
frequency of the modal class
C
frequency of the class preceding the modal class
D
frequency of the class succeeding the modal class

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Mix Examples - Statistics

The times,in seconds,taken by $150$ athletes to run a $110\, m$ hurdle race are tabulated below:

Class (seconds) $13.8-14.0$ $14.0-14.2$ $14.2-14.4$ $14.4-14.6$ $14.6-14.8$ $14.8-15.0$

Frequency $2$ $4$ $5$ $71$ $48$ $20$

The number of athletes who completed the race in less than $14.6\, s$ is:

Easy

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The frequency distribution table of agricultural holdings in a village is given below:

Area of land (in hectares) $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ $11-13$

Number of families $20$ $45$ $80$ $55$ $40$ $12$

Find the modal agricultural holdings of the village (in hectares).

Medium

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If mode $= 25$ and mean $= 19,$ then median $= \dots$

Medium

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If $M - \bar{x} = 2$ and $Z = 20.5$,then the median $M = \ldots$ (in $.5$)

Medium

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Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)

Class	$80-90$	$90-100$	$100-110$	$110-120$	$120-130$	$130-140$	$140-150$	$150-160$	$160-170$
Frequency	$6$	$18$	$78$	$80$	$100$	$72$	$0$	$40$	$6$

Medium

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Class (seconds)	$13.8-14.0$	$14.0-14.2$	$14.2-14.4$	$14.4-14.6$	$14.6-14.8$	$14.8-15.0$
Frequency	$2$	$4$	$5$	$71$	$48$	$20$

Area of land (in hectares)	$1-3$	$3-5$	$5-7$	$7-9$	$9-11$	$11-13$
Number of families	$20$	$45$	$80$	$55$	$40$	$12$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$ for the mode,$l = \ldots \ldots \ldots$

Similar Questions

The times,in seconds,taken by $150$ athletes to run a $110\, m$ hurdle race are tabulated below: Class (seconds) $13.8-14.0$ $14.0-14.2$ $14.2-14.4$ $14.4-14.6$ $14.6-14.8$ $14.8-15.0$ Frequency $2$ $4$ $5$ $71$ $48$ $20$ The number of athletes who completed the race in less than $14.6\, s$ is:

The frequency distribution table of agricultural holdings in a village is given below: Area of land (in hectares) $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ $11-13$ Number of families $20$ $45$ $80$ $55$ $40$ $12$ Find the modal agricultural holdings of the village (in hectares).

If mode $= 25$ and mean $= 19,$ then median $= \dots$

If $M - \bar{x} = 2$ and $Z = 20.5$,then the median $M = \ldots$ (in $.5$)

Calculate the mean of the following frequency distribution: Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$ (in $.55$)

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The times,in seconds,taken by $150$ athletes to run a $110\, m$ hurdle race are tabulated below:

Class (seconds) $13.8-14.0$ $14.0-14.2$ $14.2-14.4$ $14.4-14.6$ $14.6-14.8$ $14.8-15.0$

Frequency $2$ $4$ $5$ $71$ $48$ $20$

The number of athletes who completed the race in less than $14.6\, s$ is:

The frequency distribution table of agricultural holdings in a village is given below:

Area of land (in hectares) $1-3$ $3-5$ $5-7$ $7-9$ $9-11$ $11-13$

Number of families $20$ $45$ $80$ $55$ $40$ $12$

Find the modal agricultural holdings of the village (in hectares).

Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)