In the following state whether $\mathrm{A = B}$ or not :
$A = \{ 2,4,6,8,10\} ;B = \{ x:x$ is positiveeven integer and $x\, \le \,10\} $
In the following state whether $\mathrm{A = B}$ or not :
$A = \{ 2,4,6,8,10\} ;B = \{ x:x$ is positiveeven integer and $x\, \le \,10\} $
$A=\{2,4,6,8,10\}$
$B = \{ x:x{\rm{ }}$ is a positive even integer and $x\, \le \,10\} $
$=\{2,4,6,8,10\}$
$\therefore A=B$
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