In the following state whether $A=B$ or not :
$A=\{4,8,12,16\} ; B=\{8,4,16,18\}$
In the following state whether $A=B$ or not :
$A=\{4,8,12,16\} ; B=\{8,4,16,18\}$
$A=\{4,8,12,16\} ; B=\{8,4,16,18\}$
It can be seen that $12 \in A$ but $12 \notin B$
$\therefore A \neq B$
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