In the following reaction:text{Aldehyde} + te | vedclass

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(B) The formation of acetal from an aldehyde and an alcohol is a nucleophilic addition reaction.This reaction is highly sensitive to steric hindrance.

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$HCHO$ and $MeOH$

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(B) The formation of acetal from an aldehyde and an alcohol is a nucleophilic addition reaction.This reaction is highly sensitive to steric hindrance.$Rate \propto \frac{1}{	ext{Steric Crowding}}$.$HCHO$ is the least sterically hindered aldehyde,and $MeOH$ is the least sterically hindered alcohol.Therefore,the combination of $HCHO$ and $MeOH$ provides the fastest and most efficient reaction to form an acetal.

In the following reaction:
$\text{Aldehyde} + \text{Alcohol} \xrightarrow{HCl} \text{Acetal}$
$HCHO \qquad ^tBuOH$
$CH_3CHO \qquad MeOH$
The best combination for the formation of acetal is:

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In the following reaction:$\text{Aldehyde} + \text{Alcohol} \xrightarrow{HCl} \text{Acetal}$$HCHO \qquad ^tBuOH$$CH_3CHO \qquad MeOH$The best combination for the formation of acetal is: