In the following reaction sequence,the major product $P$ is formed. Glycerol reacts completely with excess $P$ in the presence of an acid catalyst to form $Q$. Reaction of $Q$ with excess $NaOH$ followed by the treatment with $CaCl_2$ yields $Ca$-soap $R$,quantitatively. Starting with one mole of $Q$,the amount of $R$ produced in gram is. . . . [Given,atomic weight: $H=1, C=12, N=14, O=16, Na=23, Cl=35, Ca=40$ ]

The major product of the following reaction sequence is

Match List-$I$ with List-$II$.
List-$I$:
$(a)$ $\text{Benzene} \xrightarrow[\text{CuCl}]{\text{CO, HCl, Anhyd. AlCl}_3} \text{Benzaldehyde}$
$(b)$ $R-CO-CH_3 + NaOX \rightarrow$
$(c)$ $R-CH_2-OH + R'COOH \xrightarrow{\text{Conc. H}_2\text{SO}_4}$
$(d)$ $R-CH_2COOH \xrightarrow[(ii) H_2O]{(i) X_2/\text{Red P}} R-CH(X)COOH$
List-$II$:
$(i)$ $\text{Hell-Volhard-Zelinsky reaction}$
(ii) $\text{Gattermann-Koch reaction}$
(iii) $\text{Haloform reaction}$
(iv) $\text{Esterification}$
Choose the correct answer from the options given below.

How will you prepare the following compounds from benzene? You may use any inorganic reagent and any organic reagent having not more than one carbon atom:
$(i)$ Methyl benzoate
$(ii)$ $m$-Nitrobenzoic acid
$(iii)$ $p$-Nitrobenzoic acid
$(iv)$ Phenylacetic acid
$(v)$ $p$-Nitrobenzaldehyde.

The product $(A)$ of the reaction is:

An organic compound $(A)$ (molecular formula $C_{8}H_{16}O_{2}$) was hydrolysed with dilute sulphuric acid to give a carboxylic acid $(B)$ and an alcohol $(C)$. Oxidation of $(C)$ with chromic acid produced $(B)$. $(C)$ on dehydration gives but$-1-$ene. Write equations for the reactions involved.