In the following nuclear reaction,$x$ is: ${ }_{13} Al^{27} + { }_2 He^4 \rightarrow { }_0 n^1 + X$

Kinetic energy of the emitted $\alpha-$ particle in the $\alpha-$ decay of ${}_{88}^{226}Ra$ will be,.......... $MeV$ (where $m_{\alpha} = 4.00260 \, u$,$m({}_{88}^{226}Ra) = 226.02540 \, u$ and $m({}_{86}^{222}Rn) = 222.01750 \, u$).

One of the fusion reactions in the sun is given by ${ }_{1}^{2} H+{ }_{1}^{1} H \rightarrow{ }_{2}^{3} He+\gamma+Q$. Calculate the energy $Q$ released in the reaction. (in $MeV$)

Under certain circumstances,a nucleus can decay by emitting a particle more massive than an $\alpha$-particle. Consider the following decay processes:
$_{88}^{223} Ra \rightarrow _{82}^{209} Pb + _{6}^{14} C$
$_{88}^{223} Ra \rightarrow _{86}^{219} Rn + _{2}^{4} He$
Calculate the $Q$-values for these decays and determine that both are energetically allowed.

If in a nuclear fusion process the masses of the fusing nuclei are ${m_1}$ and ${m_2}$ and the mass of the resultant nucleus is ${m_3}$, then

In a fission reaction ${}_{92}^{236}U \to {}^{117}X + {}^{117}Y + n + n$,the binding energy per nucleon of $X$ and $Y$ is $8.5\,MeV$,whereas that of ${}^{236}U$ is $7.6\,MeV$. The total energy liberated will be about: