In the following diagram,which particle has t | vedclass

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(D) The deflection $y$ of a charged particle moving through a uniform electric field $E$ is given by the formula $y = \frac{E e x^2}{2 m v^2}$,where $

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$D$

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(D) The deflection $y$ of a charged particle moving through a uniform electric field $E$ is given by the formula $y = \frac{E e x^2}{2 m v^2}$,where $e$ is the charge,$m$ is the mass,$v$ is the velocity,and $x$ is the horizontal distance traveled.Assuming the electric field $E$,velocity $v$,and distance $x$ are the same for all particles,we have $y \propto \frac{e}{m}$.This means the deflection $y$ is directly proportional to the specific charge ratio $e/m$.Looking at the diagram,particle $A$ shows the maximum deflection in the upward direction,and particle $D$ shows the maximum deflection in the downward direction. Since the magnitude of deflection is greatest for $A$ and $D$,they have the highest $e/m$ ratios. Given the options,$D$ is the standard answer for such problems where downward deflection is considered.

In the following diagram,which particle has the highest $e/m$ value?

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