In the following conversion,C_6H_5CN xrightar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction sequence is as follows:$1$. Benzonitrile $(C_6H_5CN)$ reacts with methylmagnesium bromide $(MeMgBr)$ followed by acid hydrolysis $(H_

Vedclass · Accepted Answer

$III$

Vedclass · Answer

(C) The reaction sequence is as follows:$1$. Benzonitrile $(C_6H_5CN)$ reacts with methylmagnesium bromide $(MeMgBr)$ followed by acid hydrolysis $(H_3O^+)$ to form acetophenone $(C_6H_5COCH_3)$ as product $X$.$2$. Acetophenone $(C_6H_5COCH_3)$ contains a methyl ketone group,which undergoes the iodoform reaction with $NaOH/I_2$ followed by acidification $(H_3O^+)$ to produce benzoic acid $(C_6H_5COOH)$ as product $Y$.Thus,$X$ is acetophenone and $Y$ is benzoic acid,which corresponds to option $III$.

In the following conversion,
$C_6H_5CN$ $\xrightarrow[(ii) H_3O^+]{(i) MeMgBr} X$ $\xrightarrow[H_3O^+]{NaOH/I_2} Y$
the major products $X$ and $Y$,respectively are

Similar Questions

The end product $(C)$ in the following reaction is:

$Ph-CH_3$ $\xrightarrow{CrO_2Cl_2} (A)$ $\xrightarrow{conc. KOH} Ph-CH_2OH + (B)$
Product $(B)$ of the above reaction is:

Consider the following sequence of reactions:
Isopropyl benzene $\xrightarrow{O_2} x$ $\xrightarrow[H_2 O]{H^{+}} y + z$
The incorrect statement about $z$ is:

$Ph-C(=O)-CH_3 \xrightarrow{NaOCl} A + \text{salt}$
$A + CH_3-C(=O)-CH_3 \rightarrow B$
$B$ is

What type of reaction is the formation of aldol from aldehyde?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the following conversion,$C_6H_5CN$ $\xrightarrow[(ii) H_3O^+]{(i) MeMgBr} X$ $\xrightarrow[H_3O^+]{NaOH/I_2} Y$the major products $X$ and $Y$,respectively are