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(C) The reaction sequence is the industrial preparation of phenol and acetone from cumene (isopropyl benzene).$1.$ Isopropyl benzene (cumene) reacts w

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$z$ on reaction with $CH_3 MgBr$ followed by hydrolysis gives $2^{\circ}$ alcohol

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(C) The reaction sequence is the industrial preparation of phenol and acetone from cumene (isopropyl benzene).$1.$ Isopropyl benzene (cumene) reacts with $O_2$ to form cumene hydroperoxide $(x)$.$2.$ Cumene hydroperoxide on acid hydrolysis gives phenol $(y)$ and acetone $(z = CH_3COCH_3)$.Analysis of statements about acetone $(z)$:$A.$ Acetone contains a $CH_3CO-$ group,so it gives a positive iodoform test ($CHI_3$ yellow ppt). This is a correct statement.$B.$ Reduction of acetone $(CH_3COCH_3)$ with $H_2/Pd$ gives isopropyl alcohol $(CH_3CH(OH)CH_3)$. This is a correct statement.$C.$ Reaction of acetone $(CH_3COCH_3)$ with $CH_3MgBr$ followed by hydrolysis gives tert-butyl alcohol $(CH_3C(OH)(CH_3)_2)$,which is a $3^{\circ}$ alcohol,not a $2^{\circ}$ alcohol. This is an incorrect statement.$D.$ Acetone is a ketone and does not reduce Fehling's reagent. This is a correct statement.Therefore,the incorrect statement is $C$.

Consider the following sequence of reactions:
Isopropyl benzene $\xrightarrow{O_2} x$ $\xrightarrow[H_2 O]{H^{+}} y + z$
The incorrect statement about $z$ is:

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Consider the following sequence of reactions:Isopropyl benzene $\xrightarrow{O_2} x$ $\xrightarrow[H_2 O]{H^{+}} y + z$The incorrect statement about $z$ is: