In the following circuit,PN-junction diodes D | vedclass

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(C) The circuit consists of three parallel branches between the nodes connected to the $R/4$ resistors. Let the node after the first $R/4$ resistor be

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$(ii) = (iii) < (i)$

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(C) The circuit consists of three parallel branches between the nodes connected to the $R/4$ resistors. Let the node after the first $R/4$ resistor be $X$ and the node before the last $R/4$ resistor be $Y$. The total resistance is $R_{AB} = R/4 + R_{XY} + R/4 = R/2 + R_{XY}$.$(i) V_A = -10\,V, V_B = -5\,V$: Here $V_A $(ii) V_A = -5\,V, V_B = -10\,V$: Here $V_A > V_B$. All diodes are forward biased $(ON)$. The three branches with resistance $R$ are in parallel,so $R_{XY} = R/3$. Thus,$R_{AB} = R/2 + R/3 = 5R/6$.$(iii) V_A = -4\,V, V_B = -12\,V$: Here $V_A > V_B$. All diodes are forward biased $(ON)$. Similarly,$R_{XY} = R/3$. Thus,$R_{AB} = R/2 + R/3 = 5R/6$.Comparing the values: $(ii) = (iii) < (i)$.

In the following circuit,$PN$-junction diodes $D_1, D_2$ and $D_3$ are ideal. For the following potentials of $A$ and $B$,find the correct increasing order of equivalent resistance between $A$ and $B$:
$(i) V_A = -10\,V, V_B = -5\,V$
$(ii) V_A = -5\,V, V_B = -10\,V$
$(iii) V_A = -4\,V, V_B = -12\,V$

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In the following circuit,$PN$-junction diodes $D_1, D_2$ and $D_3$ are ideal. For the following potentials of $A$ and $B$,find the correct increasing order of equivalent resistance between $A$ and $B$:$(i) V_A = -10\,V, V_B = -5\,V$$(ii) V_A = -5\,V, V_B = -10\,V$$(iii) V_A = -4\,V, V_B = -12\,V$