A wire suspended vertically from one of its ends is stretched by attaching a weight of $200\ N$ to the lower end. The weight stretches the wire by $1\ mm$. Then the elastic energy stored in the wire ......... $J$

- A
$0.1$

- B
$0.2$

- C
$10$

- D
$20$

Given : $\sigma$ is the compressibility of water, $\rho$ is the density of water and $K$ is the bulk modulus of water. What is the energy density of water at the bottom of a lake $‘h’$ metre deep ?

The elastic energy stored in a wire of Young's modulus $Y$ is

When shearing force is applied on a body, then the elastic potential energy is stored in it. On removing the force, this energy

The length of a rod is $20\, cm$ and area of cross-section $2\,c{m^2}$. The Young's modulus of the material of wire is $1.4 \times {10^{11}}\,N/{m^2}$. If the rod is compressed by $5\, kg-wt$ along its length, then increase in the energy of the rod in joules will be

A wire is suspended by one end. At the other end a weight equivalent to $20\, N$ force is applied. If the increase in length is $1.0\, mm,$ the ratio of the increase in energy of the wire to the decrease in gravitational potential energy when load moves downwards by $1\, mm,$ will be